PLEASE HELP!!!!!!!!!!!!!! please?

Question

A motorcycleist is going to try to jump across as many buses as he can. The takeoff rampy-thing makes an angle = 18.4 degrees above the horizontal.The landing ramp is identical to the takeoff ramp. The buses are parked side by side, and each bus is 2.74 m wide. The dud leaves the ramp with a speed of v = 31.0 m/s. What is the maximum number of buses over which the guy can jump?

i am so confussed and i have no idea how to do this!!!!!! i just don't even know where to start. please help me. i really am trying and im tired and i need to know how to do this last problem. i have finished the rest of my physics problems and i am just stumped! please help me. Thank you so much!!!!!!!!!!!!

Answer 1

The fact that he leaves the ramp at an angle of 18.4 degs says that he has a vertical and horizontal component of velocity.
The horizontal part. vcos 18.4 times the time of flight gives the horizontal dist he goes, 31 *.9488 t. We don't know what t is. The vertical part is going to help. Since the vertical part of the vel is 0 at the higherst point of flight we can use
vsin 0 degs - v(initial) sin 16.4 = -gt. Or
31* .282 = 9.8 t or t = .89 secs. But that's the time to reach the highest point of his arc. Since he continues after that to the same height from which he took off, we double the time,
So, t =1.78 secs.
So the horizontal distance he goes is 31 *.9488 t = 52.35 m
Now for the end:
The busses are 2.74 m wide
52.35/2.74 = 19 + busses. So 19 is the answer.
This is not an easy problem for someone who says she' s so confussed. If you need more help with it>
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Answer 2

Hint:
If his ramp angle is 18.4 degrees,
his vertical velocity is 31m/s x sine 18.4,
his horizontal velocity is 31 m/s x cos. 18.4.
With the 'G` you know how long he stays up.
(Vert. Vel. / G) x 2 (Time up + time down)
With his horizontal velocity, (which remains
constant), you know how far he jumps.
(The top of the ramps is assumed to be at
the roof level of the buses.)

Cute avatar!

Answer 3

don't u need to know the height of the buses? and the mass of the motorcyclist & bike? ( for the formula 1/2 x mass x velocity^2, to calculate kinetic energy.) this question has too much missing info. try something else.