An electron is released a short distance above
Earth's surface. A second electron directly
below it exerts an electrostatic force on the
first electron just great enough to cancel the
gravitational force on it.
The value of Coulomb's constant is
8.98755x 10^9 N / m2xC2 and the acceleration
of gravity is 9.81 m/s^2 :
How far below the first electron is the second?
2007-09-12 15:20:29 · 2 answers · asked by TheThing 2 in Science & Mathematics ➔ Physics
You should probably also mention that the charge of an electron is 1.6022X10^(-19) Coulombs.
Doug
2007-09-12 15:45:15 · answer #1 · answered by doug_donaghue 7 · 1⤊ 0⤋
♠ Sir, I’m ready to solve this! But
just wonder was that answer also wrong?
http://answers.yahoo.com/question/index;_ylt=ApvaTm9hhFqkp0hb8ApqQ_Xty6IX;_ylv=3?qid=20070402184023AAsInz7
2007-09-12 15:57:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋