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What is the process and how do i get a solution

2007-09-12 15:17:47 · 3 answers · asked by Eri 1 in Science & Mathematics Mathematics

3 answers

-8=-2x^2+6x
or,-8+2x^2-6x=0
or,x^2-3x-4=0 [dividing both sides by 2]
or,x^2-4x+x-4=0
or,x(x-4)+1(x-4)=0
or,(x-4)(x+1)=0
therefore,either x-4=0 or x+1=0
If x-4=0,then x=4
If x+1=0,then x= -1
x=4 or -1 ans

2007-09-12 15:27:43 · answer #1 · answered by alpha 7 · 0 0

-8 = -2x^2 + 6x => 2x^2 - 6x -8 = 0
(2x - 8)(x + 1) = 0

x = 4 or -1

2007-09-12 22:27:46 · answer #2 · answered by Beardo 7 · 0 0

-2

2007-09-12 22:21:19 · answer #3 · answered by da ddddddd 1 · 0 0

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