How do I write an equation for this sequence:
3, 5, 9,. 17, 33, 65 [...] 4097
2007-09-12 14:36:12 · 6 answers · asked by ☆ 2 in Science & Mathematics ➔ Mathematics
multiples of two
3 + 2^1 = 5
5 + 2^2 = 9
9 + 2 ^3 = 17
and so on and so forth
2007-09-12 14:45:03 · answer #1 · answered by Rachel V 1 · 0⤊ 0⤋
The difference between the terms in your sequence are 2,4,8,16,32,...
You may recognize them as powers of 2.
This allows you to express your sequence as 3+2^n where n starts at 0 and goes to ???
2007-09-12 14:46:56 · answer #2 · answered by L B 4 · 0⤊ 0⤋
a(n) = 2^n + 1
n = 1: a(1) = 2^1 + 1 = 3
n = 2: a(2) = 2^2 + 1 = 5
n = 3: a(3) = 2^3 + 1 = 9
etc.
2007-09-12 14:47:01 · answer #3 · answered by Marvin 4 · 1⤊ 0⤋
a_n= 3+2^(n-1) n>1
2007-09-12 14:42:37 · answer #4 · answered by santmann2002 7 · 0⤊ 1⤋
i got (2^(n-1)) + 1
2007-09-12 14:46:44 · answer #5 · answered by Geno 2 · 0⤊ 0⤋
(nx2)-1
65,129,257,513,1025,2049,4097
2007-09-12 15:04:06 · answer #6 · answered by Jo 1 · 0⤊ 0⤋