2 (to the xth power) = 9
How do I determine the value of x?
2007-09-12 14:32:02 · 6 answers · asked by bokonon1000 1 in Science & Mathematics ➔ Mathematics
2**x = 9
ln(2) 2**x = ln(2) 9
x = ln (2) 9
2007-09-12 14:38:15 · answer #1 · answered by Computer Guy 7 · 0⤊ 0⤋
2^x = 9
log (2^x) = log 9
x*log 2 = log 9
x = log 9/log 2 = 0.954/.301 = 3.17
Check by doing 2^3.17
2007-09-12 21:39:41 · answer #2 · answered by Marvin 4 · 0⤊ 0⤋
You have to use natural logarithm (ln)
ln 9/ln 2 = approx. 3.16 = x
2007-09-12 21:38:55 · answer #3 · answered by SoulDawg 4 UGA 6 · 0⤊ 0⤋
log both sides
log( 2^x) = log( 9)
=> x* log 2 = log 9
x = (log 9)/(log 2)
2007-09-12 21:37:20 · answer #4 · answered by Sugar Shane 3 · 0⤊ 0⤋
2^x = 9
x*log(2) = log(9)
x = log(9)/log(2)
= 3.1699 ...
2007-09-12 21:37:00 · answer #5 · answered by de4th 4 · 0⤊ 0⤋
2^x = 9
x * ln(2) = ln(9)
x = ln(9) / ln(2)
2007-09-12 21:38:22 · answer #6 · answered by Pakyuol 7 · 0⤊ 0⤋