Dice question?

Question

List the probabilities for the eleven possible outcomes for throwing a pair of dice. Check is they add up to 1.

Answer 1

2: 1/36
3: 2/36 = 1/18
4: 3/36 = 1/12
5: 4/36 = 1/9
6: 5/36
7: 6/36 = 1/6
8: 5/36
9: 4/36 = 1/9
10: 3/36 = 1/12
11: 2/36 = 1/18
12: 1/36

so the total is (1+2+3+4+5+6+5+4+3+2+1)/36 = 36/36 = 1.

Answer 2

Dice are labeled 1 to 6, so two dice, the possibilities are 2 to 12.

2, choice is 1+1
3, choice is 1+2 or 2+1
4, choice is 1+3, 2+2, or 3+1
5, choice is 1+4, 2+3, 3+2, or 4+1
6, choice is 1+5, 2+4, 3+3, 4+2, or 5+1
7, choice is ...

from there, add up the total number of choices, so far there are 15 for the ones I have done.

Your probability of those above is 1/15 for rolling a 2, 2/15 for rolling a 3, 3/15 for rolling a 4, etc.

You should be able to figure the rest out.

Answer 3

2 1+1 1/36 = 3%
3 1+2, 2+1 2/36 = 6%
4 1+3, 2+2, 3+1 3/36 = 8%
5 1+4, 2+3, 3+2, 4+1 4/36 = 11%
6 1+5, 2+4, 3+3, 4+2, 5+1 5/36 = 14%
7 1+6, 2+5, 3+4, 4+3, 5+2, 6+1 6/36 = 17%
8 2+6, 3+5, 4+4, 5+3, 6+2 5/36 = 14%
9 3+6, 4+5, 5+4, 6+3 4/36 = 11%
10 4+6, 5+5, 6+4 3/36 = 8%
11 5+6, 6+5 2/36 = 6%
12 6+6 1/36 = 3%

Answer 4

just set up a table with 1-6 on the top and 1-6 along the side
like
----1 2 3 ....
----------------------
1 | 2 3 4 ...
2 | 3 4 5 ...
3 | 4 5 6 ...
...
when you're done you'll have 36 entries so you add up all the times you get a certain outcome and divide it by 36 to give you your probability then if you add up all the probabilities you will get 1

hope this helps

Answer 5

Dice 1 + Dice 2 = Roll (#ofCombinations)
1+1= 2 (1)
1+2, 2+1 = 3 (2)
1+3,2+2,3+1 = 4 (3)
1+4,2+3,3+2,4+1 = 5 (4)
1+5,2+4,3+3,4+2,5+1=6 (5)
1+6,2+5,3+4,4+3,5+2,6+1=7 (6)
2+6,3+5,4+4,5+3,6+2= 8 (5)
3+6,4+5,5+4,6+3= 9 (4)
4+6,5+5,6+4 = 10 (3)
5+6,6+5 = 11 (2)
6+6 = 12 (1)

Total possible combinations (36)
Probability is just (# of combinations)/36

so for a roll of 7 you would have probablity of 6/36 = 1/6 = 16.6%

Answer 6

with two die, the 11 outcomes are the sum of the two die:
(possibilities are 2 through 12)

sum: combinations of die
2: 1,1
3: 1,2 - 2,1
4: 1,3 - 3,1 - 2,2
5: 1,4 - 4,1 - 2,3 - 3,2
6: well you get the gist, you can finish this table on your own

when done, count up the total different number of possibilites (n)
(or calculate it if you know the rather simple formula)
then the probability for each outcome is the number of different ways each has, divided by the previously determined n

for example, 2 can only come about in one way (1,1), so its probability is 1/n
calculate the probability like this for each of the eleven outcomes and sum them up to equal 1. as soon as your done, your mom will have a cookie for you.