English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Find all the numbers with the property that when the number is added to itself the sum is the same as when the number is multiplied by itself.

What's the best way to go about solving this question?

2007-09-12 13:20:30 · 3 answers · asked by beeboroachgoingon197 1 in Science & Mathematics Mathematics

3 answers

If the number is x, then by adding it to itself you get x+x = 2x, and by multiplying it by itself you get x*x = x^2. So we want
x^2 = 2x
<=> x^2 - 2x = 0
<=> x(x-2) = 0
<=> x = 0 or x-2 = 0
<=> x = 0 or x = 2.

2007-09-12 13:25:44 · answer #1 · answered by Scarlet Manuka 7 · 0 0

0 and 2

2007-09-12 20:26:17 · answer #2 · answered by Anonymous · 0 0

what u have stated is that x^2=2x

so x must be 2 or 0

2007-09-12 20:32:37 · answer #3 · answered by GOLD-FLAW 2 · 0 0

fedest.com, questions and answers