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f (x) = x^2 + 1

find the equation of the tangent line at the point (2, 5)
the answer is y = 4x - 3
how do i get to this answer? please show steps and explain them as much as possible. thanks

2007-09-12 13:15:21 · 1 answers · asked by Adam 2 in Science & Mathematics Mathematics

1 answers

The derivative of the function is the gradient of the tangent line.

f'(x) = 2x by the power rule: d/dx x^n = nx^(n-1).
So f'(2) = 4.
So the tangent line has gradient 4 and passes through (2, 5). So it must have equation y-5 = 4(x-2)
<=> y = 4x - 3.

2007-09-12 13:21:26 · answer #1 · answered by Scarlet Manuka 7 · 0 0

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