HELPP I NEED MAJOR HELPP PLEASSEe?

Question

A motorcycle daredevil is attempting to jump across as many buses as possible. The takeoff ramp makes an angle = 18.6° above the horizontal, and the landing ramp is identical to the takeoff ramp. The buses are parked side by side, and each bus is 2.74 m wide. The cyclist leaves the ramp with a speed of v = 32.0 m/s. What is the maximum number of buses over which the cyclist can jump?

Answer 1

since we know the speed, we can compute flight time as twice the time to apogee, or t*2 from the following equation.
Since the vertical speed will be 0 at apogee
0=sin(18.6)*32-g*t
or t=sin(18.6)*32/g

double this for total flight time, or t'=2*t and compute the horizontal distance as
cos(18.6)*32*t' and divide by the width of the busses so
#busses=
integer(cos(18.6)*32*t'/2.74)

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