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constant speed of the horse is 10.0 m/s, and the man is initially 3.00 m above the level of the saddle. (a) what must be the horizontal distance between the saddle and the limb when the man makes his move? (b) how long is he in the air?

2007-09-12 13:04:54 · 1 answers · asked by mary s 1 in Science & Mathematics Physics

1 answers

b. He is in the air t = sqrt(2s/a) = 0.782 s
a. Hor distance = vt = 7.82 m

2007-09-12 14:08:12 · answer #1 · answered by kirchwey 7 · 0 0

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