The punter on a football team tries to kick a football so that it stays in the air for a long "hang time." If the ball is kicked with an initial velocity of 23.6 m/s at an angle of 58.5° above the ground, what is the "hang time"?
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2007-09-12 12:35:46 · 3 answers · asked by Marianna E 1 in Science & Mathematics ➔ Physics
http://www.wooster.edu/physics/jrIS/Files/Ryan.pdf
From that you should be able to find the equations you're looking for and solve it yourself. I'll even give you a hint... it's on page 1
2007-09-12 12:47:59 · answer #1 · answered by promethius9594 6 · 0⤊ 0⤋
the flight time is twice the time to apogee
v(t)=0 at start and apogee
0=sin(58.5)*23.6-g*t
solve for t and double it for hang time.
j
2007-09-12 12:40:59 · answer #2 · answered by odu83 7 · 1⤊ 0⤋
4.106 s
Find out the vertical component of the velocity using trig then use -v=v+at then multiply t by 2
v=20.122 as discovered by trig
a= -9.8
t= the great unknown
solve for t
2007-09-12 12:50:17 · answer #3 · answered by dougness86 4 · 0⤊ 1⤋