So the problem is 2x(3y-5x)+4xy - 8x(squared)
2007-09-12 12:27:57 · 9 answers · asked by sweetkels10 2 in Science & Mathematics ➔ Mathematics
10xy-18x(squared)
2007-09-12 12:31:51 · answer #1 · answered by hoffster12 4 · 0⤊ 0⤋
2x(3y - 5x) + 4xy - 8x² =
6xy - 10x² + 4xy - 8x² =
10xy - 18x²
2007-09-12 19:36:03 · answer #2 · answered by Philo 7 · 0⤊ 0⤋
= 2x(3y - 5x) + 4xy - 8x^2
= 6xy - 10x^2 + 4xy - 8x^2
= 10xy - 18x^2
Answer: 10xy - 18x^2
2007-09-16 04:11:57 · answer #3 · answered by Jun Agruda 7 · 3⤊ 0⤋
2x(3y-5x) + 4xy - 8x^2
6xy - 10x^2 + 4xy -8x^2
-18x^2+10xy
2x(5y - 9x)
2007-09-12 19:36:21 · answer #4 · answered by mohanrao d 7 · 1⤊ 0⤋
first we have 6xy-10x^2+4xy-8x^2
group the xy
gives
10xy-10x^2-8x^2
group x^2
gives
10xy-18x^2
now divide both sides by the common factor 2x
gives
2x(5y-9x)
hope that helps
2007-09-12 19:41:05 · answer #5 · answered by GOLD-FLAW 2 · 0⤊ 0⤋
distribute the 2x to the 3y and the -5x. then combine like terms.
2007-09-12 19:38:17 · answer #6 · answered by dumbbrunnett88 3 · 0⤊ 0⤋
6xy-10x(squared) +4xy -8x(squared).
10xy -18x(squared)
2007-09-12 19:32:49 · answer #7 · answered by Katee 2 · 0⤊ 0⤋
6xy-10x2+4xy-8x2
10xy-18x(squared)
2007-09-12 19:33:51 · answer #8 · answered by Mr. Anderson 3 · 0⤊ 0⤋
10xy-18x
2007-09-12 19:52:17 · answer #9 · answered by Jaybear (: 2 · 0⤊ 0⤋