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A football player kicks a football with an initial speed of 13 m/s at an angle above the horizontal of 30 degrees.

a.) what are the initial components of the balls velocity?
b.) How much time will it take to reach the peak of it's motion?
c.) How much time (from the instant of the kick) will it take to reach the final position?
d.) What is the max height the ball will reach?
e.) How far from the football player (in the horizontal direction) will the ball reach it's peak?
f.) What is the final x position of the ball when it strikes the ground (assuming that x (knot) = 0)

Would really appreciate any help, even if it is just describing the steps/formulas and leaving me to do the calculations. Thanks!

2007-09-12 12:25:39 · 2 answers · asked by Jamie H 1 in Science & Mathematics Physics

2 answers

a) x=cos(30)*13
y=sin(30)*13

b) The apogee is
v(t)=0=sin(30)*13-.5*g*t
solve for t>0
t=2*sin(30)*13/g

c) using t above, the flight time is twice the time to apogee.

d)
max height uses t from b in the following equation

y(t)=sin(30)*t-.5*g*t^2

e) The flight distance uses the time calculated in c, let's call it t'
x(t')=cos(30)*13*t'

j

2007-09-12 12:31:44 · answer #1 · answered by odu83 7 · 0 0

If the piece separates gently (and not with an explosion as in case of a hearth cracker rocket ) then this is going to fly area via area as no exterior rigidity has acted on the stone or the piece. So the perfect answer is determination a million. In case of an explosion halfway this is going to rely close to separation. The small piece can pass in any random direction (no longer inevitably horizontal) and shop on with diverse parabolic direction.

2016-11-15 02:00:08 · answer #2 · answered by ? 4 · 0 0

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