The boy on the tower of height h = 12 m in the figure below throws a ball a distance of x = 50 m, as shown.?

Question

at what speed in m/s is the ball thrown

Answer 1

Since there is no diagram, I will assume that he ball is thrown horizontally and lands a distance of 50 m from directly below where it was thrown.

Equations of motion are
x(t)=50=v0*t
y(t)=0=12-.5*g*t^2

solve for v0

50/v0=t
0=12-.5*g*50^2/v0^2
use g=10

v0=sqrt(2500/2.4)
v0=32.3 m/s
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