a candy store sells boxes of candy containing caramels and cremes. each box sells for 12. 50 and holds 30 pieces of evenly sized candy. if caramels cost .25 to produce and the cremes cost .45 to produce, how many of each should be in a box to make a profit of $3?
2007-09-12 11:29:59 · 4 answers · asked by Sara H 1 in Education & Reference ➔ Homework Help
Let x = # of caramels
Let y = # of cremes
12.50 - .25x - .45y = 3
x + y = 30
Solve the second equation for x , and then substitute into the first equation
x = 30 - y
12.50 - .25(30 - y) - .45y = 3
12.50 - 7.5 + .25y - .45y = 3
5 - .2y = 3
-.2y = -2
y = 10
x + 10 = 30
x = 20
So there must be 20 caramels and 10 cremes to make a $3 profit.
2007-09-12 11:47:19 · answer #1 · answered by gateach 5 · 0⤊ 0⤋
10 cremes & 20 caramels
2007-09-12 18:40:49 · answer #2 · answered by Charlene M 2 · 0⤊ 0⤋
x + y = 30
x = 30 - y
x*0.25 + y*0.45 = 12.50 - 3 = 9.5
x + 1.8y = 38 = 30 - y + 1.8 y = 30 + 0.8 y
y = 8/0.8 = 10
x = 20
20 caramels, 10 cremes
2007-09-12 18:38:30 · answer #3 · answered by Beardo 7 · 0⤊ 0⤋
3.70
2007-09-12 18:34:05 · answer #4 · answered by sammyrrudolph 1 · 0⤊ 0⤋