Algebra 2 homework help (equation of a line)?

Question

Show that the equation of the line having x-intercept 'a' and y-intercept 'b' is 'bx + ay = ab'?

That's all it says, and its only a worksheet, not out of my textbook. So I really don't know what is being asked. Any help would be appreciated!

Answer 1

y = mx + b

m = slope

slope = (y1 - y2) / (x1 - x2)

bx + ay = ab

Subtract bx on both sides.

ay = -bx + ab

Divide both sides by a

y = (-b/a) x + b

-b/a = slope

b = y-intercept (y-coordinate) OR (0,y{int})

a = x-intercept (x-coordinate) OR (x{int},0)

(y{int} - 0) / (0 - x{int}) = -y{int} / x{int}

So this is proved.

y = (-b/a) x + b

Answer 2

x intercept is when y = 0, so when substitute y=0 in the eq
bx = ab x = a point is (a,0)

y intercept is when x = 0, so when substitue x = 0 in the eq
ay = ab y = b point is (0,b)

Answer 3

x-intercept = a --> (a,0)
y-intercept = b --> (0,b)
y(x) = mx + d
y(a) = ma + d = 0
y(0) = m(0) + d = b well we already know that d = b
m = -b/a
y(x) = (-b/a)x + b
multiply by a: ay = -bx + ab
bx + ay = ab

Answer 4

a million. positioned the equation into y=mx +b form via looking out the help of those 2 factors. locate out the slope that's y1-y2 / x1-x2 and plug that during for m. replace a style of things in for x and y. Then locate out b. Then write as y = (your slope)x + (your b) 2. Neither could properly be factored. So use the quadratic formula (google it). ax2 + bx + c is the form for each equation. Now in simple terms take each and every of those values and plug it into the quadratic formula.