How exactly are compounds with a number outside the bracket named? Would this be just Lead Nitrate? Or Lead (II) Nitrate? Or something completely different?
2007-09-12 09:50:34 · 7 answers · asked by azaa 3 in Science & Mathematics ➔ Chemistry
It's Lead (II) nitrate, lead (2+) nitrate, lead dinitrate, nitric acid lead (2+) salt, Plumbous nitrate
Molecular formula: Pb(NO3)2
The subscript number outside the brackets denotes 2 valence electrons of Lead to combine with the Single valence of the Nitrate molecule.
(Plumbic Nitrate = Pb(NO3)4...Lead (IV) Nitrate. (4 Lead valence electrons).
2007-09-12 13:23:32 · answer #1 · answered by Norrie 7 · 0⤊ 0⤋
Lead(II)Nitrate.
The number outside the brackets to the right, indicates the number of sets of brackets used, in this case two sets of the 'nitrate' anion.
DO NOT confuse with a number at the left hand side of the formula, this number indicates the required number of molecules needed in a reaction; sometimes referred to as the molar ratio.
Lead is in oxidation state '2' indicated by the Roman numerals in side the brackets.
2007-09-12 17:18:54 · answer #2 · answered by lenpol7 7 · 0⤊ 0⤋
Lead Nitrate
http://www.jtbaker.com/msds/englishhtml/l3130.htm
2007-09-12 17:01:27 · answer #3 · answered by Steve K 4 · 0⤊ 0⤋
The Stock system is lead(II) nitrate. The other is plumbous nitrate. Alternatively, there is lead(IV) nitrate and plumbic nitrate.
2007-09-12 17:01:03 · answer #4 · answered by steve_geo1 7 · 0⤊ 0⤋
Lead (II) nitrate.
2007-09-12 16:58:26 · answer #5 · answered by Showaddywaddy 5 · 0⤊ 0⤋
lead nitrate
2007-09-13 06:49:40 · answer #6 · answered by Enny 1 · 0⤊ 0⤋
lead (II) nitrate
2007-09-12 17:13:09 · answer #7 · answered by ffangelgrl 2 · 0⤊ 0⤋