Factor completely 2x^2 + 15x = 8?

Question

How do I factor this problem completely???

Answer 1

There's a slight terminological problem here. You DON'T "factor" an equation, that is something with terms or expressions on both sides of an ' = ' sign. You factor appropriate expressions.

What you CAN say is "Solve this equation by factoring." That process would proceed as follows. Take the 8 to the other side of the equation. That gives you:

2 x^2 + 15 x - 8 = 0.

NOW, the LHS DOES factor, giving you:

(2 x - 1)(x + 8) = 0.

Thus the solution to the original equation, obtained by factoring an appropriately re-written version of it, is:

x = 1/2 or x = - 8.

Live long and prosper.

Answer 2

2x² + 15x = 8

Transpose 8

2x² + 15x - 8 = 8 - 8

2x² + 15x - 8 = 0

The middle term is + 15x

Find the sum of the middle term

Mulltiply the first term 2 times the last term 8 equals 16 and factor

The factors of 16 ae

1 x 16. . .←. .use these factors
2 x 8
4 x 4

+ 16 and - 1 satisfy the sum of the middle term

Insert + 16x and - 1x into the equation

2x² + 15x - 8 - 0

2x² + 16x - 1x - 8 = 0

group factor

(2x² + 16x) - (2x - 8) = 0

2x(x + 8) - 1(x + 8 ) = 0

(2x - 1)(x + 8) = 0

- - - - - - -- s-

Answer 3

first thing you have to do is move everything to the same side. this gives 2x^2+15x-8.
now factor the minus signs tells you that the signs of the two factors will be different. your looking for a combination of multiples of 2 and 8 that make 15. so the factored version would be
(2x-1)(x+8)=0

Answer 4

2x^2 + 15x = 8
2x^2 + 15x - 8 = 0
(2x - 1)(x + 8) = 0

2x - 1 = 0, 2x = 1, x = 1/2
x + 8 = 0, x = - 8

Answer: x = 1/2, x = - 8

Answer 5

solve not factor
2x^2 + 15x = 8
2x^2+15x-8=0
(2x -1 )(x +8 )=0
2x-1=0 ,x+8=0
x=1/2 ,x=-8

Answer 6

2x^2 + 15x - 8 = 0
(2x -1)(x + 8) = 0

x = 1/2 or -8