10:00. When will Lee meet Mark?
2007-09-12 08:56:24 · 5 answers · asked by V for Vindicated 1 in Science & Mathematics ➔ Physics
distance = 94.t1
distance = 117.t2
94t1 = 117t2
t1 = t2 + 2
94(t2+2) = 117t2
94t2 + 188 = 117t2
188 = 23t2
t2 = 8.174 hours
t2 = 8 hours and 10 minutes
therefore meet at 16:10 ...
2007-09-12 09:09:57 · answer #1 · answered by aussie_east_ender 2 · 0⤊ 0⤋
I assume Mark & Lee are LEAVING from the same place too?
Use the standard formula:
speed = distance/time
Note 2 important facts:
1. Mark's distance is the same as Lee's distance.
2. Mark's TIME is 2 hours MORE than Lee's time.
So, let d = Mark's distance = Lee's distance
Let t = Lee's time.
Therefore, Mark's time is (t+2)
For Mark:
94 km/hr = d/(t+2)
or:
d = (94 km/hr)(t+2)
For Lee:
117 km/hr = d/t
or:
d = (117 km/hr)(t)
Since both the d's are equal, we have:
(94 km/hr)(t+2) = (117 km/hr)(t)
Finally, just solve that equation for "t". We said that t is Lee's travel time (in hours), so add that travel time to 10:00, and that will tell you when Lee meets Mark.
2007-09-12 09:13:07 · answer #2 · answered by RickB 7 · 0⤊ 0⤋
If we call time t in hours measured from Lee's start (i.e from 10 am) then the distance between Lee and Mark is 188 - 23t (188 being their distance apart at 10am and 23 being their difference in speed). This expression reaches zero when 23t = 188 i.e when t =188/ 23 = 8.174 which means they meet at 6:10:24.4 pm on the same day.
Bramble
2007-09-12 09:19:04 · answer #3 · answered by Bramble 7 · 0⤊ 0⤋
Assume that they left at two hours apart, and started from the same point.
94*(2+x)=117X
x=8.173913= 8hours and 10 minutes.
They will meet after Lee traveling 8hours and 10 minutes . It could be 6:10am or pm.
2007-09-12 09:40:52 · answer #4 · answered by naive 1 · 0⤊ 0⤋
94T+188 = 117T
188 = 23T
T=188/23=8hr 10min
6:10
2007-09-12 09:09:47 · answer #5 · answered by Info_Please 4 · 0⤊ 0⤋