Using this equation:
4As + 3O2 ---> 2As2O3
What is the maximum amount of As2O3 which could be produced by reacting 10.0 grams of As with excess oxygen?
2007-09-12 08:44:40 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
As MW = 74.922 g/mole
10 g = 10 g * mole/74.922g = 0.133 mole As
4 Mole As --> 2 mole As2O3
so the max As2O3 you'll get is 0.133/2 mole = 0.067 mole
As2O3 MW = 197.841 g/mole
0.067 mole As2O3 = 0.067 mole* 197.841g/mole =
13.2 g As2O3
2007-09-12 08:57:38 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋
Atomic weights: As=75 O=16 As2O3=198
10.0gAs x 1molAs/75gAs x 2molAs2O3/4molAs x 198gAs2O3/1molAs2O3 = 132g As2O3
2007-09-12 15:53:41 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
The atomic weight of Arsenic is 74.9216 grams / mole.
The atomic weight of Oxygen is 15.999 grams / mole.
10 grams of AS is 10 / 74.9216 moles = .13347 moles.
For every mole of AS in the compound there is 1.5 moles of oxygen, so there is .13347 * 1.5 = .200 moles, so the oxygen weighs .200 * 15.999 = 3.203 grams.
So the As2O3 weighs 13.203 grams.
Steve got his answer in before mine, but he's wrong, he's off by a decimal place.
2007-09-12 15:54:11 · answer #3 · answered by kimmyisahotbabe 5 · 0⤊ 1⤋