Cr2(C2O4)3 is the formula
2007-09-12 08:41:00 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
If you multiply out the oxalate ligand you get a molecular formula of , remember (C3O4) x 3 = C6O12:
Cr2C6O12
So the empirical formula is (simplest ratios):
CrC3O6
2007-09-12 08:47:19 · answer #1 · answered by Dr Oz 3 · 0⤊ 0⤋
Chromium Oxalate
2016-10-14 09:44:49 · answer #2 · answered by ? 3 · 0⤊ 0⤋
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What is the empirical formula of chromium(III) oxalate?
Cr2(C2O4)3 is the formula
2015-08-24 14:32:42 · answer #3 · answered by Quinn 1 · 0⤊ 0⤋
If a .109g sample contains 38.28% iron, then it contains .3828*.109, or .0417, grams of iron. Therefore, it also contains (.109-.0417), or .0673, grams of C2O4(2-). .0673 grams of C2O4(2-) x 1 mol / 88g = 7.64x10^-4 mol C2O4(2-) .0417 grams of Fe x 1 mol / 55.85g =7.46x10^-4 mol Fe 7.64x10^-4 / 7.46x10^-4 = 1.024. This means that for every 1 ion of C2O4, 1.024 ions of iron are present. Because the results are so close to 1:1 (they only do not appear so because of rounding), it can be concluded that the empirical formula of the compound is FeC2O4, which can be written out as either Iron II Oxalate or Ferrous Oxalate.
2016-03-19 21:46:32 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Cr2(C2O4)3 is the empirical formula also. One cannot divide through by any number to get simpler (lower) whole-number subscripts.
2007-09-12 08:45:50 · answer #5 · answered by steve_geo1 7 · 2⤊ 0⤋