ti -83 simple question?

Question

2x+1/x-3
when i put this in the caluclator the graph is the isotope or the line that the graph can not reach is 3. That means that the two curve lines sould move to the right but when i do that it is not happening. What am i doing wrong.

Answer 1

u might have to put parentheses around 1/x

Answer 2

Be sure you enter the equation as (2x-1)/(x-3). You should get a vertical asymptote at x =3 and a horizontal asymptote at y= 1. Use a window -10 to 10 for both x and y.