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thanks if yu can help, i don't know where to begin

2007-09-12 08:02:10 · 7 answers · asked by Boo Radley 4 in Science & Mathematics Mathematics

7 answers

5x^5*y^3*(-xy^4)
=-5x^6.y^7 ans

2007-09-12 08:08:44 · answer #1 · answered by MAHAANIM07 4 · 1 1

I have two problems with this:
(1) I don't know what you want to do with this;
(2) this is not a well-formed formula: the *- in the middle isn't a legal combination.
Is this, perhaps, equivalent to
5x^5 * y^3 * ((-x) * y^4) ?

If so, you have a relatively friendly product of x's and y's. All you need to do is count how many of each are multiplied together (use the commutative and associative laws to gather x's on the left, y's on the right), and then count on your fingers to get the proper exponent for each. Move the negation out front, and you're done.

2007-09-12 08:12:07 · answer #2 · answered by norcekri 7 · 0 0

(5x^5)(y^3)(-xy^4) I've put in brackets to make certain that this is indeed what you want tackled. I think that"s why you used the *. In any case that's my assumption.

This is a multiplication problem.
(5x^5)(y^3)(-xy^4) means
(5)(x)(x)(x)(x)(x)(y)(y)(y)(-x)(y)(y)(y)(y)
I'm going to re-write (-x) as (-1)(x)
Now, since multiplication is associative , (meaning you can multiply in any arrangement you like, as
2 X 4 X 3 instead of 2 X 3 X 4)
I shall re-arrange to get like terms next to each other'
(-1)(5)(x)(x)(x)(x)(x)(x)(y)(y)(y)(y)(y)(y)(y)
We write this as -5x^6y^7
That's it IF I understood the problem correctly.

Returning to the problem, 5x^5y^3*-xy^4, they
wanted you to see that a -1 was understood to be in front of the xy^4 term, and that you could combine the like terms just by adding the exponents.

2007-09-12 08:37:51 · answer #3 · answered by Grampedo 7 · 0 0

replace each and every of the x's with -4 y=(-4^3)+(4(-4)^2)-5 y=-sixty 4+sixty 4-5 y=0.5 y=-5 yet another ordinary way is to comprehend that's -5, is the reality that the 1st 2 areas have x's, however the -5 does not. y=mx+b. y will consistently equivalent b in each and every person of those issues....ex: y=2x+6.......y=6 yet another ex: y=3x^2 +5x-2.........y=-2

2016-11-15 01:30:24 · answer #4 · answered by weberg 4 · 0 0

Since you don't specify what you want to do, and since it's Algebra, I'll assume the * was by mistake and the - sign means you are subtracting xy^4, and all you want to do is factor it out... therefore the answer would be

xy^3 (5x^4 - y)

Since you x^1 and y^3 are the highest you can factor.

2007-09-12 08:21:04 · answer #5 · answered by ejb.luna 2 · 0 0

5 x ^ 5 y ^ 3 * - x y ^ 4=-5x^6y^7

2007-09-12 08:12:20 · answer #6 · answered by Anonymous · 0 0

This is a polynomial. You can simplify it thus:

-5x^6y^7

2007-09-12 08:17:18 · answer #7 · answered by gebobs 6 · 0 0

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