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NH3, H2SO4, CH3OH, CH3COOH

Please help me to understand why you are ranking them the way that you do. There are so many rules and exceptions it seems for acids and bases that it is hard for me to rank a group of more than two.

2007-09-12 07:27:14 · 3 answers · asked by alyssia_o6 1 in Science & Mathematics Chemistry

3 answers

Order: NH3 < CH3OH < CH3COOH < H2SO4

Logic:

(1) Inorganic/mineral acids are always VERY strong acids, stronger than most (if not all) organic acids - hence H2SO4

(2) The amines/amino compounds are basic, not very acidic, hence this NH3 is the weakest of all these acids.

This leaves CH3OH and CH3COOH. To compare acidities it is usually helpful to compare the stabilities of the conjugate bases (deprotonated form):

CH3OH --> CH3O(-) + H(+)
CH3COOH --> CH3COO(-) + H(+)

The most stable conjugate base has the most acidic parent molecule. In this case, CH3COO(-) is more stable than the CH3O(-) because the is resonance stabilization in the CO2(-) group. As this conjugate base is more stable, the CH3CO2H molecule is more acidic than the CH3OH molecule.

This leave us with the ordering:
NH3 < CH3OH < CH3COOH < H2SO4

Hope this helps!

2007-09-12 07:37:48 · answer #1 · answered by Dr Oz 3 · 1 0

Evolution isn't a concept relating to the muse of existence. It would not belong in this checklist. the concept of Evolution by ability of organic determination, explains the verity of existence and how it have been given to the form this is now. It would not say something approximately origins.

2016-12-13 07:14:55 · answer #2 · answered by ? 4 · 0 0

NH3 < CH3OH < CH3COOH < H2SO4

2007-09-12 07:33:07 · answer #3 · answered by steve_geo1 7 · 0 0

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