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that is 9 divided by the cube root of "x"

2007-09-12 05:07:03 · 3 answers · asked by Andrew H 1 in Science & Mathematics Mathematics

3 answers

You can rewrite the function as
f(x)=9*x^(-1/3)
which may help you see how to obtain the derivative.
Bring the power down to the front (as a product), and
subtract the exponent by 1.
f'(x)=9*(-1/3)*x^(-4/3)
f'(x)= -3/(x^(4/3))

2007-09-12 05:14:38 · answer #1 · answered by Not Eddie Money 3 · 0 0

d[9x^(-1/3)]/dx =
(-1/3)(9)x^(-1/3 - 1) =
-3x^(-4/3) =
-3/[x•cube root of x]

2007-09-12 12:14:05 · answer #2 · answered by Philo 7 · 0 0

d/dx(9x^-1/3)
=-3x^(-4/3)

2007-09-12 12:21:31 · answer #3 · answered by swati s 2 · 0 0

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