If I invented an absolute temperature scale (The Jack scale) where 1000J was the boiling point of water.....?

Question

What would be the freezing point?

Answer 1

It would be about 732J.

You can use any existing absolute scale to show this. For example, on the Kelvin scale, boiling = 373.15K and freezing = 273.15K. This means that (on any absolute scale), freezing should be about 73% as high as boiling ((273.15/373.15), to be exact).

Answer 2

If the freezing point of water in *F is 32*F and its boiling point in *F is 212*F then the freezing point of water in Jack Scale is 10*C or 1000*J / 100*C

Solution: 0*C=32*F=10*J
1000*J divide it by 100*C then multiply it by 0*C

= 10*J