1, 3/2/ 9/4, 27/8,?,? please help me find the next 2 terms!!!???

Answer 1

If you notice the numerator of each new term is multiplying the previous term by 3 and the denominator of each new term is multiplying the previous term by 2

so 27*3 81
------- = ----
8*2 16

and the next term:

81*3 243
------- = -----------
16*2 32

The next two terms are 81/16 , 243/32

Answer 2

1, 3/2 = 1 & 1/2, 9/4 = 2 & 1/4, 27/8 = 3 & 3/8,
The next 2 terms will be 27 x 3 / 8 x 2 = 81 / 16 &
81 x 3 / 16 x 2 = 243 / 32

This is assumed that top multiplies by 3 and bottom multiples by 2 each increase in sequence.

Answer 3

81/16 243/32

3 9 27 81 243 is part of the pattern
(3 x 1) (3 x 3) (3 x 9) (3 x 27) (3 x 81)
going up by powers of 3

2 4 8 16 32 is another part of it
(2) (2 x 2) (2 x 2 x 2) (2 x 2 x 2 x 2) (2 x 2 x 2 x 2 x 2)

Answer 4

1, 3/2, 9/4, 27/8, 81/ 16, 243/ 32

Basically you multiply the previous term with 3/2 to get the next term.

Answer 5

My guess would be 81/16 ; 243/32

The first number (1) in the sequence can be expressed as 1/1.

For each of the next three terms in the sequence, you take the numerator (top number of the fraction) of the term before and multiply it by 3 to get the new numerator. Then you take the denominator (bottom number of the fraction) of the term before and multiply it by 2 to get the denominator.

If you follow those same rules for two more terms, you get as a result: 81/16; 243/32.

Answer 6

3^4/2^4 = 81/16 and

3^5/2^5 = 243/32.

The nth term will be: 3^n/2^n.

Hope this helps, Twiggy.

Answer 7

The Top number triples and the bottom number doubles, so it would be 81/16 and... (You don't need me for this).... 243/32

Answer 8

81/16 , 243/32