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(6x {raised}3-8x{raised}2-14x+13) divided by (3x+2)

2007-09-12 03:32:47 · 2 answers · asked by countess_von_katz 2 in Science & Mathematics Mathematics

2 answers

looks like time for you to practice your long division

2x^2(3x+2) = 6x^3+4x^2

6x^3-8x^2-14x+13 minus
6x^3+4x^2 equals

-12x^2-14x+13

-4x(3x+2)=-12x^2-8x

-12x^2-14x+13 minus
-12x^2-8x =

-6x+13

-2(3x+2)=-6x-4

-6x+13 minus
-6x-4 equals

17

6x^3-8x^2-14x+13 divided by 3x+2
equals 2x^2 - 4x - 2 + 17/(3x +2)

2007-09-12 04:18:57 · answer #1 · answered by trogwolf 3 · 0 0

(6x^3-8x^2 -14x +13)/(3x+2)
= 2x^2-4x-2 +17/(3x+2)
Done by long division

2007-09-12 10:49:02 · answer #2 · answered by ironduke8159 7 · 0 1

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