Find the range of the function on the given domain....?

Question

f(x)=x^2-4 -2
explain your working please or just list out the steps.

pre-calculas sucks...i hate it

Answer 1

You have to evaluate all the values of y between all those values of x in the domain.
With a line you would only need to use the endpoints, but with a parabola, you should use the endpoints and whatever value makes the squared portion zero.
Use x = -2, x =0, and x = 3
x = -2.......f(x) = 0
x = 0........f(x) = -4
x = 3........f(x) = 5
The range of numbers is -4

Answer 2

f(x) = x² - 4

Since domain is -2 Substitute all values between -2 and +3 for x.

For x = -2
f(x) = 4 - 4 = 0

For x = -1
f(x) = 1 - 4 = -3

For x = 0
f(x) = 0 - 4 = -4

For x = 1
f(x) = 1 - 4 = -3

For x = 2
f(x) = 4 - 4 = 0

For x = 3
f(x) = 9 - 4 = 5

We get the results as 0, -3, -4, -3, 0, 5

Here, the lowest number is -4 and greatest is 5.

Therefore, the range is -4

Answer 3

f(x) = x^2 -4 where -2 f(-2) = (-2)^2 - 4 = 0
f(0) = -4 = minimum value
f(3) = 3^2 - 4 = 5
So range of f(x) is -4 =< f(x) < 5

Answer 4

if x=-2, f(x)=0
if x=3, f(x)=5
range (0,5) The points 0 and 5 are not in the range.
The domain includes all numbers between -2 and 3 (excluding -2,3)
The range all numbers betwen (0,5) excluding 0 and 5.