Why does glycine not exist in the uncharged form, but rather in salt (zwitterion) form?
2007-09-12 03:22:16 · 4 answers · asked by jim m 3 in Science & Mathematics ➔ Chemistry
The molecule of glycine undissociated would not be soluble in water. since water is a polar liquid , it must contain polar molecules (with one or several charges) and so , the two functions of the molecule must be dissociated froming NH3+ and COO- groups.
2007-09-12 03:51:23 · answer #1 · answered by maussy 7 · 0⤊ 0⤋
Glycine Zwitterion
2016-10-20 06:30:39 · answer #2 · answered by ? 4 · 0⤊ 0⤋
The NH2 of glycine is basic enough to remove the proton from the carboxylic acid. This proton abstraction is facilitated by a 5-membered transition state. In other words draw out glycine in its full form. Now count the number of atoms starting from the H on the carboxylic acid to the N. The number of atoms is 5. The lone pair electrons on the N can very easily abstract the H from the carboxylic acid since it is a "5-membered transition state." 5-membered and 6-membered transition states are very low energy and are favored. Hope this helps.
2007-09-12 03:52:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
yes (:
2016-05-17 21:35:31 · answer #4 · answered by sallie 3 · 0⤊ 0⤋