1/[1+0.3e^(-0.276t)] = [e^(0.276t)]/ [(e^(0.276t)) + 0.3]?

Question

I'm trying to follow an example solution, but having trouble with how the author got from:
1/[1+0.3e^(-0.276t)]
to
= [e^(0.276t)]/ [(e^(0.276t)) + 0.3]
How could this have been done?

thanks Scarlet Manuka, was just forgeting something obvious.

Answer 1

Multiply top and bottom by e^(0.276t):

1/[1+0.3e^(-0.276t)]
= [e^(0.276t)] / [e^(0.276t) + 0.3 e^(-0.276t) e^(0.276t)]
= [e^(0.276t)] / [e^(0.276t) + 0.3 e^(-0.276t + 0.276t)]
= [e^(0.276t)] / [e^(0.276t) + 0.3 e^0]
= [e^(0.276t)] / [e^(0.276t) + 0.3]

Answer 2

6