y(squared)-3y-12
solve for y?
2007-09-11 21:22:52 · 3 answers · asked by MTak 2 in Science & Mathematics ➔ Mathematics
I think i need to factor it out to solve for the answer(s) of y
2007-09-11 21:34:03 · update #1
[3 + sqrt(57)]/2 & [3-sqrt(57)]/2...
I'm assuming you meant solve for the equation y^2-3y-12 = 0
Use the quadratic formula.
2007-09-11 21:26:52 · answer #1 · answered by SoulDawg 4 UGA 6 · 0⤊ 0⤋
y^2 - 3y - 12 = 0
y^2 - 3y = 12
y = 5.274917217
Answer: 5.274917217
Proof:
= (5.274917217)^2 - 3(5.274917217)
= 27.82475165 - 15.82475165
= 12
2007-09-16 00:37:34 · answer #2 · answered by Jun Agruda 7 · 3⤊ 0⤋
y(squared)-3y-12=0
y(squared)-3y=12
*applying completing the square:
(-3/2)(squared)=9/4
*add to both sides:
y(squared)-3y+(9/4)=12+(9/4)
*factor:
(y-3/2)(y-3/2)=(48+9)/4
(y-3/2)(squared)=57/4
sqrt(y-3/2)=sqrt(57/4)
y-3/2=+/- sqrt(57/4)
*y=3/2+sqrt(57/4)
*y=3/2-sqrt(57/4)
^_____^
2007-09-12 06:43:16 · answer #3 · answered by jimrey12 1 · 0⤊ 0⤋