i dont understand factoring this
a^3-125
2007-09-11 21:08:33 · 8 answers · asked by rawrzor 1 in Science & Mathematics ➔ Mathematics
(a - 5)(a^2 + 5a + 25)
Use the difference of cubes formula.
In general, x^3 - y^3 = (x-y)(x^2 + xy + y^2).
Substitute a for x and 5 for y. 5 cubed is 125
2007-09-11 21:14:28 · answer #1 · answered by SoulDawg 4 UGA 6 · 1⤊ 0⤋
Use the formula: (a^3 - b^3) = (a - b)(a^2 + ab + b^2)
with b=5
a^3 - 125 = a^3 - 5^3 = (a - 5)(a + 5a + 25)
2007-09-12 04:16:55 · answer #2 · answered by Amit Y 5 · 0⤊ 1⤋
heres the equation (x-y)(x^2+xy+y^2) then you just extract the a^3 into just one so that just a now your a is your x and 125 is broken up 5 x 25 right, so 5 is now your y and substitute the x's and y's
(a-5)(a^2+5a+25)
and your done.
2007-09-12 04:18:57 · answer #3 · answered by THE GOOD NIGHT 6 · 0⤊ 0⤋
Here the people above gave you the answer what your need is this to factor cubes
a3 + b3 = (a + b)(a2 – ab + b2)
a3 – b3 = (a – b)(a2 + ab + b2)
Factoring cubes and squares are different
2007-09-12 04:22:43 · answer #4 · answered by cronohl 3 · 0⤊ 0⤋
a^3 = 125
a^2 = 25
a = 5
2007-09-16 00:28:21 · answer #5 · answered by Jun Agruda 7 · 3⤊ 0⤋
(a-5)(a^2+5a+25)
2007-09-12 04:14:36 · answer #6 · answered by kimbokrn 2 · 0⤊ 0⤋
I think its (a-5)^2 X a+5, I'm not sure though.
2007-09-12 04:14:38 · answer #7 · answered by Alan 2 · 0⤊ 2⤋
are you looking for the differrence of two squares....if so i believe the answer is prime because there an odd exponent and an odd variable
2007-09-12 04:14:47 · answer #8 · answered by arod_69 1 · 0⤊ 2⤋