2007-09-11 21:02:48 · 11 answers · asked by platinumbutterfly713 1 in Science & Mathematics ➔ Mathematics
(3 x y ² + 12 y ²) = (3 y ²) (x + 4)
(2 x ² - 11 x + 5) = (2 x - 1 )(x - 5)
2 x y + 8 y = (2 y)(x + 4)
(8 x ² + 2 x - 3) = (4 x + 3) (2 x - 1):-
(3 y ²) (x + 4) (4x + 3) (2x - 1)
----------------------------------------
(2x - 1)(x - 5) (2y)(x + 4)
3y (4x + 3)
--------------
(2) (x - 5)
2007-09-15 20:01:26 · answer #1 · answered by Como 7 · 0⤊ 0⤋
FOIL ability you multiply the 1st, Outer, inner, and final (4x + 3)(2x + 5) First 4x * 2x = 8x^2 Outer 4x * 5 = 20x inner 3 * 2x = 6x and final 3 * 5 = 15 So including thes values we get 8x^2 + 20x + 6x +15 = 8x^2 +26x +15
2016-11-15 00:30:27 · answer #2 · answered by vereen 4 · 0⤊ 0⤋
(3xy²+12y²) over (2x²-11x+5) devided by (2xy+8y) over (8x²+2x-3)
=3y²(x+4) over (x+5)(2x-1) devided by 2y(x+4) over (2x-1)(4x+3)
=3y over (x-5) devided by 2 over (4x+3)
=3y(4x+3) over 2(x-5)
2007-09-11 21:23:37 · answer #3 · answered by ngtuhanh188 3 · 0⤊ 0⤋
Your problem is : A/B divided by C/D, right?
Change it to A*D/B*C, ie, division is multiplication by reciprocal. SO, we have
(3xy^2 + 12y^2) * (8x^2 + 2x -3)
----------------------------------------, FACTOR
(2x^2 - 11x +5) * (2xy+8y)
3y^2(x+4) * (4x +3)(2x -1)
----------------------------------, cancel terms
(2x -1 )(x -5) * 2y(x+4)
3y^2 * (4x+3)
-------------------, cancel y
(x-5) * 2y
3y*(4x+3)
-------------. Done.
2*(x-5)
2007-09-11 21:17:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋
3y(8x^+2x-3)/2(2x^-11x+5) (3xy^+12y^)=3y^(x+4) (2xy+8y)=2y(x+4)
2007-09-11 21:22:14 · answer #5 · answered by lbelfer 4 · 0⤊ 0⤋
simplify...
3y^2(x+4)/(x-5)(2x-1) divided by (2x-1)(4x+3)/2y(x+4)...
cancel out similar terms...
3y^2(4x+3)/2y(x-5), simplify further...
3y(4x+3)/2(x-5)
2007-09-15 19:18:46 · answer #6 · answered by criselda 3 · 0⤊ 0⤋
first we factor
[ (3y^2)(x+4y) / (x-5)(2x-1) ] / [ (2y)(x+4y) / (4x+3)(2x-1) ]
we then get the reciprocal and procede to multiplication
[ (3y^2)(x+4y) / (x-5)(2x-1) ] * [ (4x+3)(2x-1) / (2y)(x+4y) ]
multiply
(3y^2)(x+4y)(4x+3)(2x-1) / (x-5)(2x-1)(2y)(x+4y)
we then cancel out the same factors
(3y^2)(4x+3) / (x-5)(2y)
we then cancel y
(3y)(4x+3) / (x-5)(2)
then we simplify
(12xy+9y) / (2x-10)
2007-09-11 21:18:12 · answer #7 · answered by Hi-kun 2 · 0⤊ 0⤋
Afer simplification, it is 3y(4x+3)/2.
2007-09-11 21:18:16 · answer #8 · answered by JH G 1 · 0⤊ 0⤋
3xy2 + 12y2 8x2 + 2x - 3
----------------- . ---------------- =
2x2 - 11x +5 2xy + 8y
3y2 (x + 4) (4x + 3)(2x - 1)
----------------- . ------------------- =
(2x - 1)(x - 5) 2y(x + 4)
3y (4x + 3)
-------------- =
2(x - 5)
12xy + 9y
-------------
2x - 10
2007-09-11 21:20:02 · answer #9 · answered by matheson 2 · 0⤊ 0⤋
start by simplifying first..look at your numerator..you have things in common...
2007-09-11 21:09:10 · answer #10 · answered by arod_69 1 · 0⤊ 0⤋