i accidentally said solve...can you please help me factor this equation step by step?? thank you.
2007-09-11 20:28:13 · 4 answers · asked by antonini 1 in Science & Mathematics ➔ Mathematics
It's not factorable.
The discriminant is 55^2 - 4(89)(34) = -9079. Since it is negative, we can't factorise this quadratic into linear factors (unless we use complex numbers, which I assume you don't want to do; even then, since 9079 is not a square number, the only factors have irrational numbers in them).
2007-09-11 20:37:29 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 1⤋
The best way for that is to discuss first its discriminant.
See,
a = 89
b = 55
c = 34
b^2 - 4ac = 55^2 - 4 * 89 * 34
= - 9076
The coefficients are rational and discriminant,
b^2 - 4ac is less than 0.
-9076 is less than 0.
Hence, the roots are a pair of complex conjugates.
2007-09-12 04:27:16 · answer #2 · answered by Elmer B 2 · 0⤊ 0⤋
Factors of 89 (1, 89), and factors of 34 (17,2)
(89x + 17)(x + 2 )
Sorry, it can NOT be factored!
2007-09-12 03:36:07 · answer #3 · answered by pbb1001 5 · 0⤊ 1⤋
No factors as (55)² - 4(89)(34) = -9079 which is negative
2007-09-12 03:38:50 · answer #4 · answered by tancy2411 4 · 0⤊ 1⤋