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Vector m has a magnitude of 5 m directed east
Vector p has a magnitude of 4 m directed 35 degrees west of due north.
1)What are the magnitude and direction of vector m + vector n
2)What are the magnitude and direction of vector n - vector m

I don't get how to draw the diagram to set up my problem, what exactly is 35 degrees west of due north? is the angle still going to be 35? (its in the 2nd quadrant isn't it)?
Also how would I find the magnitude and direction...thanks

2007-09-11 17:36:45 · 4 answers · asked by superman 4 in Science & Mathematics Mathematics

4 answers

Look at a protractor if you need help visualizing. You are correct that this angle will be in the 2nd quadrant. North is straight up at 90º, west is to the left at 180º. So, 35º W of N is 125º.
Mag = 5
Direct = 125º

The vector of 5m is at 0º (east)
Mag = 4
Direct = 0º

2007-09-11 17:40:55 · answer #1 · answered by bedbye 6 · 0 0

35 degrees West of due north is the vector that starts at the origin and makes an angle of 35 degrees with the positive y-axis. The angle actually is 90+35 = 125 degrees.

So vector p has a magnitude of 5 and a direction of 125 degrees
Vector m has a magnitude of 4 and a direction of 0 degrees
For p-m m would have a magnitute of 5 and angle = 180.

2007-09-11 17:55:46 · answer #2 · answered by ironduke8159 7 · 0 0

L1: r = -3 i + 3 j + s (-8 i - 9 j) L2: r = 9 i - 10 j + t ( i - 4 j) i will replace the parameter of L2 "r" to z. L1: r = -3 i + 3 j + s (-8 i - 9 j) L2: z = 9 i - 10 j + t ( i - 4 j) -3 i + 3 j + s (-8 i - 9 j) = 9 i - 10 j + t ( i - 4 j) -3 i + 3 j -8 s i - 9 s j = 9 i - 10 j + t i - 4 t j i ( -3 - 8s) + j ( 3 - 9s) = i ( 9 + t) + j ( - 10 -4t) (-3 - 8s) = 9 + t 3 - 9s = -10 - 4t 4* (-3 - 8s) = (9 + t) * 4 3 - 9s = -10 - 4t -12 - 32s = 36 + 4t 3 - 9s = -10 - 4t - 9 - 40-one s = 26 -40-one s = 35 s = -35 /40-one 3 - 9 (-35/40-one) = - 10 -4t 3 + 315 /40-one = -10 - 4t 123/40-one + 315/40-one +410/40-one = -4t 548/40-one * a million/4 = -t - 137/40-one = t r = 9 i - 10 j -137/40-one ( i - 4 j) r = 9 i - 10j -137/40-one i + 548/40-one j r = 369/40-one i - 410/40-one j - 137/40-one i + 548/40-one j r = 232/40-one i +148/40-one j

2016-10-10 10:25:11 · answer #3 · answered by ? 4 · 0 0

http://www.frontiernet.net/~imaging/vector_calculator.html

2007-09-11 19:21:18 · answer #4 · answered by harsh_bkk 3 · 0 0

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