2007-09-11 17:29:44 · 12 answers · asked by texan3715 1 in Science & Mathematics ➔ Mathematics
= 3 (- 4) ² - 0
= 3 x 16
= 48
2007-09-14 19:41:25 · answer #1 · answered by Como 7 · 0⤊ 0⤋
First put p and q into the 3p2-4q
So 3(-4)2-4(0)
Do the multiplication first
3*-4 =-12*2= -24
4*0=0
Now you have -24 - 0
Which equals -24
2007-09-12 00:42:41 · answer #2 · answered by bluest4 2 · 0⤊ 0⤋
3p2-4q
= 3(-4)^2 - 4*0
= 3*16 - 0
= 48
2007-09-12 00:51:21 · answer #3 · answered by Siddhartha Basu 4 · 0⤊ 0⤋
HEY MICHEAL IM IN
ALGEBRA 2 SO I
KNOW THIS STUFF TRUST ME
3p2-4q first put the numbers
3*(-4)*2 - 4*0
3*(-4)=-12*2=-24
-4*0=0
-24 - 0=-24
-24 WALA
2007-09-12 00:37:57 · answer #4 · answered by paulzkool 2 · 0⤊ 0⤋
is the equation 3p2 or 3p²?
3p2-4q
= 3(-4)(2)-4(0)
= -24-0
=-24
3p²-4q
=3(-4)²-4(0)
=3(-4)(-4)-0
=48
2007-09-12 00:37:17 · answer #5 · answered by staRdUst 2 · 0⤊ 0⤋
3p2-4q=3(-4)2-4(0)=-24-0=-24.
2007-09-12 00:36:45 · answer #6 · answered by lbelfer 4 · 0⤊ 0⤋
3(-4)2 - 4(0)
(-12)2 - 0
-24 - 0
-24//
2007-09-12 00:36:14 · answer #7 · answered by Anonymous · 1⤊ 0⤋
easy, just subsitute 3(-4)2-4(0)=? work it out so 3(-4)=-12 and so on and so forth
2007-09-12 00:37:11 · answer #8 · answered by Jenn 2 · 0⤊ 0⤋
Ok, this is my answer,
3p^2 - 4q
3(16) - 4(0)
= 48
and that's how is done! Good luck!
2007-09-12 00:38:12 · answer #9 · answered by alrivera_1 4 · 0⤊ 0⤋
i suppose thats 3p^2
just replace the p with -4 and the q with 0
3(-4)^2 - 4*0
3*16-0
48
2007-09-12 00:36:22 · answer #10 · answered by Jay 4 · 0⤊ 1⤋