solve for x: ln(5x-1)-lnx=3?

Answer 1

ln(5x-1) - lnx = 3
ln [(5x-1)/x] = 3 Law of log
(5x -1)/x = e^3 Take exp on both sides
5x - 1 = xe^3
x = 1 / (5-e^3)
= -0.066

Answer 2

ln(5x-1) - lnx = 3
ln [(5x-1)/x] = 3 Law of log
(5x -1)/x = e^3 Take exp on both sides
5x - 1 = xe^3
x = 1 / (5-e^3)
= -0.066

Answer 3

For a million, positioned e to the two component. This cancels the ln. You get e^5x+a million-e^x=e^3. so, 5x+a million-x=3. 4x+a million=3. 4x=2. x=a million/2. for 2, x-2^3/2 ability the squareroot of x-a million cubed. sq. the two factors. You get x-2 cubed = sixty 4. dice root the two factors. You get x-2=4. x=6. For3, replace delta x and x into the equation. strengthen and then simplify. You get 2deltaX cases X + delta x squared + 3delta x throughout delta x. This equals 2x + delta X +3.

Answer 4

ln(5x-1) - lnx = 3
ln [(5x-1)/x] = 3
(5x -1)/x = e^3 Take exponent on both the sides
5x - 1 = xe^3
x(5-3e^)=1
x=1/5-3e^
= -0.066

Answer 5

It is an indeterminate question. Apparently, the deductions produce x = -0.0667, but this does not satisfy the equation in the real domain. Of course, it satisfies in the complex domain.

For example, you see,
for x = -0.0667,

x1=Ln(5*x-1) = 0.2877 + 3.1416i, which is not in the real domain but in the complex domain.

Answer 6

Use this property of logs:
log(a) - log(b) = log(a/b)

Then use the fact that ln(a) = b means a = e^b