let x = theta... so
sin (2x) = 0.24469 .......take the arcsin on both sides
arcsin[ sin (2x) ] = arcsin(0.24469) ... a function composed of its inverse cancel each other out
so
2x = arcsin(0.24469)
x = 1/2*arcsin(0.24469)
subsitute x back for theta
2007-09-11 15:02:03
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answer #1
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answered by Anonymous
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If you have an obscure decimal like that (AND assuming that's what they really gave you; NOT a square root or something that you yourself rounded off and copied here) then the best you you can do is just use a calculator. Take the inverse sin of 0.24469 and divide by 2.
2007-09-11 22:00:33
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answer #2
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answered by Anonymous
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Remember that, when you got a theta, there are other values that have the same theta:
sin a = sin (180o - a) if you are wroking in grads, sin (pi-a) if you use radians.
And sin a = sin (a+ k 360o) or sin (a + 2kpi).
Ilusion
2007-09-12 09:12:03
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answer #3
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answered by Ilusion 4
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(1) Find the angle the sine of which is .024469. You do this by using a calculator, or a spreadsheet, or by looking it up in a table.
(2) The angle you found in step (1) is 2θ, so divide that angle by 2 to get θ.
2007-09-11 22:02:36
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answer #4
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answered by gugliamo00 7
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theta is the angle symbol
2007-09-11 22:07:56
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answer #5
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answered by metsrule 2
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sin(2(Φ))=.024469
arcsine(sin(2(Φ))= arcsine(.024469)
2Φ=1.40211
Φ=.701
HTH
Doug
2007-09-11 22:03:42
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answer #6
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answered by doug_donaghue 7
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