Ali goes hang-gliding off a 100 m cliff, but forgets his hang glider. If he has an initial velocity of 7.9 m/s

Question

How far from the base of the cliff does ali land?

Two part answer.

Answer 1

s = (1/2)at^2
(2s)/a =t^2
t = √(2s/a)
t =√(2(100)/9.8)
t = 4.5176s
D = rt = (7.9)(4.5176) = 35.69m