say you have square root of -4; how do solve it..getting rid of the radical?
2007-09-11 14:05:29 · 6 answers · asked by GangGreen 2 in Science & Mathematics ➔ Mathematics
We know that the square root of 4 is 2, so it is 2[(radical sign)inside radical sign is -1]
If you've done "imaginary numbers," then you know that the square root of -1 is called"i"
In that case, the answer is 2i.
2007-09-11 14:10:49 · answer #1 · answered by drewbear_99 5 · 0⤊ 0⤋
The square root of -4 would equal the square root of 4 times the square root of -1. the square root of 4 =2 and the square root of -1 is represented by i. So the simplified answer would be 2i.
2007-09-11 14:17:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Congratulations, you enter imaginary number zone.
Answer is 2i (2 in imaginary number)
2007-09-11 14:08:33 · answer #3 · answered by redy_salem 2 · 0⤊ 0⤋
√-4= 2i
i is an imaginary number
2007-09-11 14:08:52 · answer #4 · answered by xandyone 5 · 0⤊ 0⤋
sqrt(-4) = sqrt(4)*sqrt(-1)= +/- 2i
Note sqrt(-1)= i
i^2 = -i^3= -i
i^4 = 1
2007-09-11 14:11:59 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
2i...
it is an imaginary nubmer.
2007-09-11 14:08:45 · answer #6 · answered by Anonymous · 0⤊ 0⤋