Coulomb's law for the force of repulsion between two charged bodies is known as an inverse square law; the force is inversely proportional to the square of the distance between the objects. For purposes of this problem,
F=C/(r^2).
Holding the charged objects at a distance of r1 apart gives a force of F1. When moving the objects to a distance of r2 apart, you observe a force F2 that is 2.9 times that of F1. This must mean that r2 = ______ r1.
Any help would be greatly appreciated.
2007-09-11 13:28:09 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Yeah, I just noticed that in the physics section, paducah_billy. I wouldn't have asked the same question twice, but it disappeared from the front page so I figured it was done for there. Anyways, thanks a lot to everyone who answered, I really appreciate the help.
2007-09-11 13:40:18 · update #1
F= C/r^2
F1 = C/r1^2
C= F1r1^2
F = F1r1/r^2
F2 =F1r1/r2^2 = 2.9F1
Thus r1/r2^2 =2.9
Hence r2 = sqrt(r1/2.9)
2007-09-11 13:51:31 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
Solve for C first.
You should get C = F * r^2.
Since C is a constant, F1 * r1^2 = F2 * r2^2
You should be able to solve it from there.
2007-09-11 13:33:58 · answer #2 · answered by Tom K 6 · 0⤊ 0⤋
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2016-09-05 10:37:48 · answer #3 · answered by ? 4 · 0⤊ 0⤋
I already answerd this
r2 = r1/sqrt(2.9)
2007-09-11 13:30:35 · answer #4 · answered by Anonymous · 0⤊ 0⤋
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2007-09-11 13:31:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋
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2007-09-11 13:31:55 · answer #6 · answered by Anonymous · 0⤊ 0⤋