(x,y) x= -3, y=-4
4(-3) -7(-4)=16
-12 +28 =16
16=16 -> point is solution of the system
-6(-3)+(-4)=14
18-4=14
14=14 -> point is solution of the system
2007-09-11 13:17:39
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answer #1
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answered by Anonymous
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The easiest way to the check if the given point is a solution to either or both equations is just to plug them in. The set up of an ordered pair is (x, y), so in this case the -3 should replace all the x-values and -4 should be inserted in place of the y-values:
4x - 7y = 16
4(-3) - 7(-4) = -12 + 28 = 16
-6x + y = 14
-6(-3) + (-4) = 18 - 4 = 14
Since the point gives you the indicated solution, then it works as a solution for the system of equations. Hope that helps!
2007-09-11 13:19:41
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answer #2
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answered by skm4usa 3
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It's not rocket science. Just plug in the x value in for the "x" in the equations. And plug in the y value for the "y" in the equations.
I'm not showing the work, do it yourself. But yes, it is a solution to the "system of equations".
2007-09-11 13:28:17
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answer #3
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answered by bdc3141 4
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test a solution by plugging it into the equation to see if it turns out true:
4(-3) - 7(-4) =? 16
-12 + 28 =? 16
16 = 16 .....................OK 1st equation
-6(-3) + (-4) =? 16
18 - 4 =? 16
14 <> 16 ..................not OK 2nd equation
so not a solution to the system.
2007-09-11 13:18:05
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answer #4
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answered by Philo 7
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This is a Glade air freshener problem -- plug it in, plug it in!!
Can x be -3 and y be -4??? plug those values in and see if it indeed equals 16 in the first equation and 14 in the second.
If it is, then it is a solution. If not, it's not.
2007-09-11 13:17:00
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answer #5
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answered by douglas 2
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4*-3 - 7*-4 = 16
-6*-3 + -4 = 14
yes
2007-09-11 13:16:40
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answer #6
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answered by Jeffrey B 1
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4(-3) - 7(-4)
= -12 - (-28)
=28 - 12
16 (yes)
-6(-3) + (-4)
=18 - 4
14 (yes)
2007-09-11 13:18:09
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answer #7
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answered by Anonymous
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fill in values of x,y into the equation and see that easy
2007-09-11 13:17:49
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answer #8
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answered by SCIENCE_MAN_88@YAHOO.COM 2
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(x - y^5)^3 = x^3 - 3x^2y^5 + 3xy^10 - y^15
2016-05-17 10:11:06
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answer #9
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answered by ? 3
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