metric conversion? can you show me the way to convert these please i will give you 5 stars please
1) 8.2 mg = _____ g
2) 7.6 kL = _______ L
3) 8.4 cm=______ mm
4) 56 daL=_____kL
2007-09-11 12:24:39 · 8 answers · asked by Anonymous in Education & Reference ➔ Homework Help
ok... i have a test tomorrow how do you get
8.2 milligram = 0.008 2 gram
2007-09-11 12:30:09 · update #1
8.2 milligram = 0.008 2 gram
7.6 kiloliter = 7 600 liter
8.4 cm=84mm
56 deciliter = 5.6 liter
2007-09-11 12:28:27 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Metrics systems work in multiples of 10
1) A milligram is a 1000th of a gram so 8.2mg = 0.0082g
2) A kiloliter is 1000 liters so 7.6 kL = 7600 L
3) A centimeter is 10 millimeters so 8.4 cm = 840 mm
4) A dekaliter is a 100th of a kiloliter so 56 daL = 0.56 kL
2007-09-11 19:31:46 · answer #2 · answered by barrmulio 2 · 0⤊ 0⤋
1) It takes 1000 mg to make 1 g,
so divide 8.2 mg by 1000 to get 8.2 mg = 0.0082 g.
2) Each kL is equal to 1000 L,
so multiply 7.6 kL by 1000 to get 7.6 kL = 7,600 L.
3) Each cm is equal to 10 mm,
so multiply 8.4 cm by 10 to get 8.4 cm = 84 mm.
4) It takes 100 daL to make 1 kL,
so divide 56 daL by 100 to get 56 daL = 0.56 kL.
2007-09-11 19:27:15 · answer #3 · answered by Cosette 3 · 0⤊ 1⤋
1 mg = 0.001g
8.2mg = 0.0082 g
1 kL = 1000 L
7.6 kL = 7600 L
1 cm = 0.01m = 10 mm
8.4 cm = 84 mm
da - sorry, not sure
2007-09-11 19:32:07 · answer #4 · answered by Beardo 7 · 0⤊ 1⤋
Metric conversions, metric conversion chart & table - online ...Online metric conversion calculator includes metric, US customary and Imperial unit conversions.
www.sciencemadesimple.com/conversions.html
2007-09-11 19:30:49 · answer #5 · answered by Frosty 7 · 0⤊ 1⤋
There's bound to be a conversion site some where on Google
2007-09-11 19:27:53 · answer #6 · answered by Damo 2 · 0⤊ 1⤋
mg-g= divide by 1000
kL-L= multiply by 1000
cm-mm= multiply by 10
daL-kL= multiply by 100
2007-09-11 19:27:44 · answer #7 · answered by sargeantb2 3 · 1⤊ 1⤋
http://www.worldwidemetric.com/metcal.htm
2007-09-11 19:27:27 · answer #8 · answered by Anonymous · 0⤊ 1⤋