2007-09-11 10:27:09 · 4 answers · asked by Zazzare 2 in Science & Mathematics ➔ Mathematics
n²-n
Given n rays sharing a common vertex, select any pair of distinct rays. For each pair, there are two angles we can measure -- one being the measure of the angle "inside" the two rays, and the other being the reflex angle "outside" these two rays (Geezah's earlier answer was didn't count the outside angles, so his count will differ from mine by a factor of two). So the total number of angles is twice the total number of distinct pairs of rays. The number of distinct pairs of objects from a set of n objects is n(n-1)/2, so the total number of angles in n rays is n(n-1) or n²-n.
Septembersong, Geezah is the name of one of the users here, who happened to answer this person's previous question.
2007-09-11 11:05:07 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
Who you callin' Geezah, sonny? Yer talkin' to Grandma here. I never larnt more 'un third grade numbers plus I don't know what kind of rays yer referrin' to. Can't see as good as I used ta anyhow, so you just grab on ta' that perfessor and mebbe the both of you can figger it out. Y'all have fun now, ya hear!
2007-09-11 17:39:19 · answer #2 · answered by Anonymous · 0⤊ 2⤋
Looking back, I find that the things I remember best are the things that came from doing my own homework.
2007-09-11 17:30:02 · answer #3 · answered by nurse_spratchet 4 · 0⤊ 0⤋
We're not working on this till Geezah gets here!
2007-09-11 18:00:59 · answer #4 · answered by knashha 5 · 1⤊ 0⤋