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12 answers

Without imaginary numbers the SQRT(-64) is NOT DEFINED.

This is because there is no real number that multiplied by itself gives a negative number.

If you trying to solve a goemetry problem, it's possible that you're trying to get a measure of a diagonal, or something related. Check the equation you should be using, it might contain a ABSOLUTE VALUE ( |n| ) operator, which will solve the problem of your negative value.

2007-09-11 09:42:57 · answer #1 · answered by murrayskull05 2 · 1 1

No, the square root of -64 is not 8. Since, like you said, you have not covered the concept of imaginary numbers yet, you can just say that -64 "has no square root", or that x^2 = -64 has "no real solution". You simply can't take the square root of a negative number, because no number on the real number line can be squared to give you back a negative number. 0*0=0, a negative times a negative is a positive, and a positive times a positive gives back a positive, so no real numer times itself can be a negative number.

Now the CUBE root of -64 is another story...

2007-09-11 09:47:53 · answer #2 · answered by Anonymous · 0 0

The short answer: Square roots of negative numbers do not have any real value. This is because there is no real number (that is, any number on the number line) which when squared will give you a negative number. If x<0, then x^2 is positive. if x>0, x^2 is positive. And if x = 0, then x^2 = 0. Since you can't square a number and get a negative number back, there is no real value for things like √-5. The long answer: It's possible to express square roots of negative numbers as "imaginary numbers". This is when you let i = √-1, and factor the square root in terms of i. For example, √-7890 = √(-1 * 9 * 2630) = 3i√2630. Any number in the form of a+bi where a and b are real are called "complex numbers". All real numbers are complex numbers where b=0. Complex numbers have lots of applications.

2016-05-17 08:06:02 · answer #3 · answered by Anonymous · 0 0

the square root of negative 64 does not exist. 8x8 is positive 64, -8 x -8 again a positive 64. The only way it will work is -8x-8 =64x-1= -64. BUT IT HAS BEEN A LONG TIME since math!

2007-09-11 09:48:58 · answer #4 · answered by zipper 7 · 0 0

No the qrt of +64 is + and - 8. You cannot take the sqrt of a negative number because you always get a positive number when you square every number whether negative or positive.

2007-09-11 09:44:48 · answer #5 · answered by Renaissance Man 5 · 0 0

Sorry, but the answer IS an imaginary number

square root(-64) = 8 i

2007-09-11 09:43:12 · answer #6 · answered by DanE 7 · 0 1

the square root of -64 is 8i, whether in geometry or not. I guess that you should not have any length that is -64 in a geometric problem because negative distances do not exist.

2007-09-11 09:43:14 · answer #7 · answered by Christophe G 4 · 0 1

if there are no imaginary numbers than the problem is impossible.


[-8*-8=64 and 8*8=64]

2007-09-11 09:42:48 · answer #8 · answered by Anonymous · 1 1

If you can't use imaginary numbers, it doesn't exist. Are you sure you mean:

sqrt(-64)

and not:

-sqrt(64)

?

The latter would be -8

2007-09-11 09:56:30 · answer #9 · answered by Anonymous · 0 0

yes 8x8=64

2007-09-11 09:42:46 · answer #10 · answered by ~~Smiley~~~ 2 · 0 1

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