An artillery shell is fired at an angle of 78.5 degrees
above the horizontal ground with an initial
speed of 1880 m/s.
The acceleration of gravity is 9.8 ms^2 :
Find the total time of fight of the shell,
neglecting air resistance. Answer in units of
min.
2007-09-11 09:24:52 · 2 answers · asked by Jaweida S 1 in Science & Mathematics ➔ Physics
Find its horizontal range, neglecting air resis-
tance. Answer in units of km.
2007-09-11 09:25:37 · update #1
Vy = 1800 * sin(78.5 deg)
t = 2Vy/g = 375.97 s = 375.97/60 min.
Vx = 1800 * cos(78.5 deg)
Hor. range = Vx*t = 140918 m = 140.918 km
Yes it's a high velocity for guns, but some real nasties showed up in WW1 and WW2 getting up to 1600 m/s or so. Quite possibly modern weapons can do at least that.
2007-09-13 01:17:19 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋
1880 m/s is kind of tough to achive for a shell
2007-09-11 09:31:25 · answer #2 · answered by Alexander 6 · 0⤊ 1⤋