solve equation:
(2n+3) (n-4)=0
could you show work please?
2007-09-11 07:37:25 · 6 answers · asked by s.s. coolio 2 in Science & Mathematics ➔ Mathematics
2 n + 3 = 0 , n - 4 = 0
2 n = - 3 , n = 4
n = - 3 / 2 , n = 4
2007-09-11 08:03:54 · answer #1 · answered by Como 7 · 2⤊ 0⤋
2n + 3 = 0
- 3 -3
2n = -3
/2 /2
n = -3/2
n - 4 = 0
+4 +4
n = 4
Depending on the context of the problem, it might or might not be appropriate for an answer to be negative, meaning it can be thrown out.
2007-09-11 14:43:31 · answer #2 · answered by Matthew K 2 · 0⤊ 0⤋
Set each part equal to 0:
2n + 3 = 0
2n = -3
n = -3/2
n - 4 = 0
n = 4
n = 4, -3/2
2007-09-11 14:42:36 · answer #3 · answered by Becky M 4 · 0⤊ 1⤋
(2n+3) (n-4)=0
either the term 2n + 3 = 0
so (subtract 3 from each side
2n =-3
then divide by 2
n = -3/2
or the term n - 4 = 0 (add 4 to each side)
n = 4
so
n = -3/2 or n = 4.
2007-09-11 14:45:53 · answer #4 · answered by tfloto 6 · 1⤊ 1⤋
you have to foil so its..2n^2-5n-12=0 then add 12 to both sides so its now 2n^2-5n=12 then n=4 because you substitute it in for n in both places and 12=12
2007-09-11 14:43:03 · answer #5 · answered by napetowneagles21 2 · 0⤊ 3⤋
tlofto is right.
2007-09-11 14:55:29 · answer #6 · answered by dcbossygirl 3 · 0⤊ 3⤋