One number is 6 more than another. If the sum of the smaller number number and 3 times the larger number is 34, find the two numbers.
2007-09-11 06:30:43 · 5 answers · asked by moni 1 in Science & Mathematics ➔ Mathematics
S= smaller number
L= larger number
S + 6 = L (Add 6 to the smaller to eqaul the bigger)
S + 3L = 34 (as given in the question 3 times the larger added to the smaller is 34)
S=L-6 from Eq 1
substatute this into Eq 2 to get:
L-6 +3L = 34
4L = 40
L = 10
S = 10-6
S=4
2007-09-11 06:48:34 · answer #1 · answered by 037 G 6 · 0⤊ 0⤋
Let x = smaller no., x + 6 = larger no.
Find the smaller no.:
x + 3(x + 6) = 34
x + 3x + 18 = 34
4x = 16
x = 4
Find the larger no.:
= 4 + 6
= 10
Answer: 4 and 10 are the smaller and larger numbers, respectively.
Proof:
= 4 + 3(10)
= 4 + 30
= 34
2007-09-11 13:43:27 · answer #2 · answered by Jun Agruda 7 · 3⤊ 1⤋
lets call the first number "A", and the second one, "B".
B=A+6.
The second equation is A + 3 B = 34.
You'll need to rearrange one equation, and stuff it into the other equation.
That should be a good start...
2007-09-11 13:40:07 · answer #3 · answered by David F 7 · 0⤊ 1⤋
a) given: x-y=6
b) given: 3x+y=34
3x-3y=18 (expanded from a)
4y=16 (calculated from above and b)
y=4 (calculated from above)
x=10 (calculated from above and a)
Smaller number = 4 bigger number = 10
2007-09-11 13:44:32 · answer #4 · answered by Ernst S 5 · 0⤊ 1⤋
x-6=y
y+3x=34
..
2007-09-11 13:37:23 · answer #5 · answered by muddypuppyuk 5 · 0⤊ 1⤋