English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

i have 2 products HCOOH and C2H5OH
i need them to react with H2SO4/ NaOH/ Na2Cr2O7/ PCl5/ NaBH4
to make as many organic products
please help!!

2007-09-11 06:17:42 · 2 answers · asked by mckenzie2 1 in Science & Mathematics Chemistry

2 answers

HCOOH + C2H5OH + H2SO4(cat) -> HCOOC2H5
HCOOH + NaOH -> HCCONa + H2O
C2H5OH + Na2Cr2O7 -> CH3COOH
C2H5OH + PCl5 -> C2H5Cl
HCOOH + PCl5 -> HCOCl (unstable)
You could also do HCOCl +C2H5OH -> HCOOC2H5
If you take the product of oxidation of C2H5OH you can also write:
CH3COOH + PCl5 -> CH3COCl
CH3COCL + C2H5OH -> CH3COOC2H5
HCOOH + NaBH4 -> CH3OH (your teacher may argue on that one but I am pretty sure that HCOOH is reactive enough to be reduced by NaBH4).
HCOOH + Na2Cr2O7 -> CO2 +H2O (again not a standard reaction but I am pretty sure it would happen with HCOOH).

2007-09-11 06:48:40 · answer #1 · answered by Christophe G 4 · 0 0

HCOOH + C2H5OH + H2SO4 ===> HCOOC2H5 Ethyl formate

HCOOH + PCl5 ===> HCOCl Formyl chloride

C2H5OH + PCl5 ===> C2H5Cl Ethyl chloride

HCOOH + H2SO4 ===> H2O + CO Carbon monoxide

C2H5OH + H2SO4 ===> CH2=CH2 Ethylene

C2H5OH + H2SO4 ===> C2H5-O-C2H5 Diethyl ether

HCOOH + NaOH ===> HCOO-Na+ Sodium formate

2007-09-11 13:49:00 · answer #2 · answered by steve_geo1 7 · 0 0

fedest.com, questions and answers